Optimal. Leaf size=326 \[ \frac{i (2-n)^2 (4-n) n (d \tan (e+f x))^{n+2} \, _2F_1\left (1,\frac{n+2}{2};\frac{n+4}{2};-\tan ^2(e+f x)\right )}{48 a^4 d^2 f (n+2)}+\frac{(1-n) (3-n) \left (n^2-4 n+1\right ) (d \tan (e+f x))^{n+1} \, _2F_1\left (1,\frac{n+1}{2};\frac{n+3}{2};-\tan ^2(e+f x)\right )}{48 a^4 d f (n+1)}+\frac{\left (n^2-7 n+13\right ) (d \tan (e+f x))^{n+1}}{48 a^4 d f (1+i \tan (e+f x))^2}+\frac{(2-n)^2 (4-n) (d \tan (e+f x))^{n+1}}{48 a^4 d f (1+i \tan (e+f x))}+\frac{(5-n) (d \tan (e+f x))^{n+1}}{24 a d f (a+i a \tan (e+f x))^3}+\frac{(d \tan (e+f x))^{n+1}}{8 d f (a+i a \tan (e+f x))^4} \]
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Rubi [A] time = 0.973092, antiderivative size = 326, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 5, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.192, Rules used = {3559, 3596, 3538, 3476, 364} \[ \frac{i (2-n)^2 (4-n) n (d \tan (e+f x))^{n+2} \, _2F_1\left (1,\frac{n+2}{2};\frac{n+4}{2};-\tan ^2(e+f x)\right )}{48 a^4 d^2 f (n+2)}+\frac{(1-n) (3-n) \left (n^2-4 n+1\right ) (d \tan (e+f x))^{n+1} \, _2F_1\left (1,\frac{n+1}{2};\frac{n+3}{2};-\tan ^2(e+f x)\right )}{48 a^4 d f (n+1)}+\frac{\left (n^2-7 n+13\right ) (d \tan (e+f x))^{n+1}}{48 a^4 d f (1+i \tan (e+f x))^2}+\frac{(2-n)^2 (4-n) (d \tan (e+f x))^{n+1}}{48 a^4 d f (1+i \tan (e+f x))}+\frac{(5-n) (d \tan (e+f x))^{n+1}}{24 a d f (a+i a \tan (e+f x))^3}+\frac{(d \tan (e+f x))^{n+1}}{8 d f (a+i a \tan (e+f x))^4} \]
Antiderivative was successfully verified.
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Rule 3559
Rule 3596
Rule 3538
Rule 3476
Rule 364
Rubi steps
\begin{align*} \int \frac{(d \tan (e+f x))^n}{(a+i a \tan (e+f x))^4} \, dx &=\frac{(d \tan (e+f x))^{1+n}}{8 d f (a+i a \tan (e+f x))^4}+\frac{\int \frac{(d \tan (e+f x))^n (a d (7-n)-i a d (3-n) \tan (e+f x))}{(a+i a \tan (e+f x))^3} \, dx}{8 a^2 d}\\ &=\frac{(d \tan (e+f x))^{1+n}}{8 d f (a+i a \tan (e+f x))^4}+\frac{(5-n) (d \tan (e+f x))^{1+n}}{24 a d f (a+i a \tan (e+f x))^3}+\frac{\int \frac{(d \tan (e+f x))^n \left (2 a^2 d^2 \left (16-7 n+n^2\right )-2 i a^2 d^2 (2-n) (5-n) \tan (e+f x)\right )}{(a+i a \tan (e+f x))^2} \, dx}{48 a^4 d^2}\\ &=\frac{\left (13-7 n+n^2\right ) (d \tan (e+f x))^{1+n}}{48 a^4 d f (1+i \tan (e+f x))^2}+\frac{(d \tan (e+f x))^{1+n}}{8 d f (a+i a \tan (e+f x))^4}+\frac{(5-n) (d \tan (e+f x))^{1+n}}{24 a d f (a+i a \tan (e+f x))^3}+\frac{\int \frac{(d \tan (e+f x))^n \left (4 a^3 d^3 \left (19-20 n+8 n^2-n^3\right )-4 i a^3 d^3 (1-n) \left (13-7 n+n^2\right ) \tan (e+f x)\right )}{a+i a \tan (e+f x)} \, dx}{192 a^6 d^3}\\ &=\frac{\left (13-7 n+n^2\right ) (d \tan (e+f x))^{1+n}}{48 a^4 d f (1+i \tan (e+f x))^2}+\frac{(d \tan (e+f x))^{1+n}}{8 d f (a+i a \tan (e+f x))^4}+\frac{(5-n) (d \tan (e+f x))^{1+n}}{24 a d f (a+i a \tan (e+f x))^3}+\frac{(2-n)^2 (4-n) (d \tan (e+f x))^{1+n}}{48 d f \left (a^4+i a^4 \tan (e+f x)\right )}+\frac{\int (d \tan (e+f x))^n \left (8 a^4 d^4 (1-n) (3-n) \left (1-4 n+n^2\right )+8 i a^4 d^4 (2-n)^2 (4-n) n \tan (e+f x)\right ) \, dx}{384 a^8 d^4}\\ &=\frac{\left (13-7 n+n^2\right ) (d \tan (e+f x))^{1+n}}{48 a^4 d f (1+i \tan (e+f x))^2}+\frac{(d \tan (e+f x))^{1+n}}{8 d f (a+i a \tan (e+f x))^4}+\frac{(5-n) (d \tan (e+f x))^{1+n}}{24 a d f (a+i a \tan (e+f x))^3}+\frac{(2-n)^2 (4-n) (d \tan (e+f x))^{1+n}}{48 d f \left (a^4+i a^4 \tan (e+f x)\right )}+\frac{\left (i (2-n)^2 (4-n) n\right ) \int (d \tan (e+f x))^{1+n} \, dx}{48 a^4 d}+\frac{\left ((1-n) (3-n) \left (1-4 n+n^2\right )\right ) \int (d \tan (e+f x))^n \, dx}{48 a^4}\\ &=\frac{\left (13-7 n+n^2\right ) (d \tan (e+f x))^{1+n}}{48 a^4 d f (1+i \tan (e+f x))^2}+\frac{(d \tan (e+f x))^{1+n}}{8 d f (a+i a \tan (e+f x))^4}+\frac{(5-n) (d \tan (e+f x))^{1+n}}{24 a d f (a+i a \tan (e+f x))^3}+\frac{(2-n)^2 (4-n) (d \tan (e+f x))^{1+n}}{48 d f \left (a^4+i a^4 \tan (e+f x)\right )}+\frac{\left (i (2-n)^2 (4-n) n\right ) \operatorname{Subst}\left (\int \frac{x^{1+n}}{d^2+x^2} \, dx,x,d \tan (e+f x)\right )}{48 a^4 f}+\frac{\left (d (1-n) (3-n) \left (1-4 n+n^2\right )\right ) \operatorname{Subst}\left (\int \frac{x^n}{d^2+x^2} \, dx,x,d \tan (e+f x)\right )}{48 a^4 f}\\ &=\frac{(1-n) (3-n) \left (1-4 n+n^2\right ) \, _2F_1\left (1,\frac{1+n}{2};\frac{3+n}{2};-\tan ^2(e+f x)\right ) (d \tan (e+f x))^{1+n}}{48 a^4 d f (1+n)}+\frac{\left (13-7 n+n^2\right ) (d \tan (e+f x))^{1+n}}{48 a^4 d f (1+i \tan (e+f x))^2}+\frac{i (2-n)^2 (4-n) n \, _2F_1\left (1,\frac{2+n}{2};\frac{4+n}{2};-\tan ^2(e+f x)\right ) (d \tan (e+f x))^{2+n}}{48 a^4 d^2 f (2+n)}+\frac{(d \tan (e+f x))^{1+n}}{8 d f (a+i a \tan (e+f x))^4}+\frac{(5-n) (d \tan (e+f x))^{1+n}}{24 a d f (a+i a \tan (e+f x))^3}+\frac{(2-n)^2 (4-n) (d \tan (e+f x))^{1+n}}{48 d f \left (a^4+i a^4 \tan (e+f x)\right )}\\ \end{align*}
Mathematica [F] time = 25.2106, size = 0, normalized size = 0. \[ \int \frac{(d \tan (e+f x))^n}{(a+i a \tan (e+f x))^4} \, dx \]
Verification is Not applicable to the result.
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Maple [F] time = 0.732, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( d\tan \left ( fx+e \right ) \right ) ^{n}}{ \left ( a+ia\tan \left ( fx+e \right ) \right ) ^{4}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\left (\frac{-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}\right )^{n}{\left (e^{\left (8 i \, f x + 8 i \, e\right )} + 4 \, e^{\left (6 i \, f x + 6 i \, e\right )} + 6 \, e^{\left (4 i \, f x + 4 i \, e\right )} + 4 \, e^{\left (2 i \, f x + 2 i \, e\right )} + 1\right )} e^{\left (-8 i \, f x - 8 i \, e\right )}}{16 \, a^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \tan \left (f x + e\right )\right )^{n}}{{\left (i \, a \tan \left (f x + e\right ) + a\right )}^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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